0=-16x^2+128x+150

Solution for 0=-16x^2+128x+150 equation:

0=-16x^2+128x+150

We move all terms to the left:

0-(-16x^2+128x+150)=0

We add all the numbers together, and all the variables

-(-16x^2+128x+150)=0

We get rid of parentheses

16x^2-128x-150=0

a = 16; b = -128; c = -150;
Δ = b2-4ac
Δ = -1282-4·16·(-150)
Δ = 25984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{25984}=\sqrt{64*406}=\sqrt{64}*\sqrt{406}=8\sqrt{406}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-8\sqrt{406}}{2*16}=\frac{128-8\sqrt{406}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+8\sqrt{406}}{2*16}=\frac{128+8\sqrt{406}}{32}
$